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Copy part of file to a new file

 
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Copy part of file to a new file
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Mo



Joined: 11 Feb 2000
Posts: 1

Post Copy part of file to a new file Reply with quote

I need to create a 24x7 job that copies a small part of a .rm type file to a new file. Any idea how can I do that? Thank you.

Fri Feb 11, 2000 5:13 pm View user's profile Send private message
SysOp
Site Admin


Joined: 26 Nov 2006
Posts: 6500

Post Re: Copy part of file to a new file Reply with quote

The best implementation depends on the size of the file and your specification of the "part" of file.

One of the solutions is to do the following:

1. // read entire file into a variable
Dim file_buffer, string
Dim part, string

FileReadAll ["your file name here"], file_buffer

2. // Get the part you want using Mid, Left, or Right statements
Mid file_buffer, [start position], [end position], part

3. // save it
FileSave ["output file name"], part

: I need to create a 24x7 job that copies a small part of a .rm type file to a
: new file. Any idea how can I do that? Thank you.

Fri Feb 11, 2000 6:23 pm View user's profile Send private message
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