question logon.exe

ello, my question is that when you sign with logon.exe for the first time, windows does not load the session, you must login into previously, then close session, after the second logon Windows starts without any problem.

Hello. What do you mean by session? user profile settings, like environment variables, or something else?

editing the file logon.log, I realized that when I start for the first time

says: "Computer is Not locked. Nothing to do."

the strange thing is that the computer is not user logged .

That message appears when it cannot find the interactive logon desktop. How do you start logon.exe?

I have logon.exe on the folder system32, for the execution I call it like this:

	Code:
	logon.exe -u administrator -p pass

I realized that when I start for the first time
I mean everty time when I restart the computer or when this started
If I do it manually and then I close session and I execute

	Code:
	logon.exe -u administrator -p pass

the season start whithout problem

What I meant is how do you launch it?

Normally it should be started by a service that starts automatically on computer startup or by a scheduled process. When you say that you run it manually, I really don't understand that. If you run it manually the desktop must be already unlocked.

is a service in java that runs the logon.exe when receiving a message through a socket.

with respect to the manual entry is that I am physically in the machine , and myself set on the field with login and password.

service in java works perfectly has all the appropriate permissions to run, messages are sent through another java application and it works perfectly but only if someone manually prior, log in the computer and then log off.

why I say that from the beginning of second session on the machine I can join a session using perfectly.

I'm sorry I still don't understand what you mean by "session"

What happens when send the same command to your java service twice waiting 10 seconds between them? As far as I understand each of them will run logon.exe, do they both fail?

What happens if after first command you logon manually, then logon and then send the second command?

Which Windows version is that?