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More on indices (SQL Server 2k8)

 
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More on indices (SQL Server 2k8)
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gemisigo



Joined: 11 Mar 2010
Posts: 1401

Post More on indices (SQL Server 2k8) Reply with quote
The following snippets are an easy way to have a peek at the indices of a table (or their details). Both work with Action set to Display Output Results.

Listing indices of the selected table:
Code:

-- index list for a table
$PROMPT(show_disabled,List disabled indices?,,,Yes No)$
$$
SELECT
   s.[schema_id]
   ,s.[name] AS [schema_name]
   ,t.[object_id] AS table_id
   ,t.[name] AS table_name
   ,i.index_id
   ,i.[name] AS index_name
   ,i.type_desc
   ,i.is_primary_key, i.is_unique, i.is_disabled, i.has_filter
   ,COUNT(ic.index_column_id) - SUM(CAST(ic.is_included_column as SMALLINT)) AS ic_count
   ,SUM(CAST(ic.is_included_column as SMALLINT)) AS iic_count
FROM
   sys.schemas s
   INNER JOIN
   sys.tables t
      ON   t.schema_id = s.schema_id
   INNER JOIN
   sys.indexes i
      ON   i.object_id = t.object_id
   INNER JOIN
   sys.index_columns ic
      ON   ic.object_id = t.object_id
      AND   ic.index_id = i.index_id
   INNER JOIN
   sys.columns c
      ON   c.object_id = t.object_id
      AND   ic.column_id = c.column_id
WHERE   i.index_id > 0
   AND   i.type IN ( 1 ,2 ) -- clustered & nonclustered only
   AND   i.is_hypothetical = 0
   AND ( i.is_disabled = 0 OR '$show_disabled$' = 'Yes')
   AND t.[object_id] = OBJECT_ID('$OBJECT$')
GROUP BY
   s.[schema_id], s.[name], t.[object_id], t.[name], i.index_id, i.[name],i.is_primary_key, i.is_unique, i.is_disabled, i.has_filter,i.type_desc
ORDER BY
   i.[name]
$$


Show the details of an index of the selected table (identified by index_id you can get by using the snippet above):
Code:

-- detailed index view for a table
$PROMPT(idix,Index id?)$
$$
SELECT
   s.[schema_id]
   ,s.[name] AS [schema_name]
   ,t.[object_id] AS table_id
   ,t.[name] AS table_name
   ,i.index_id
   ,i.[name] AS index_name
   ,i.is_primary_key, i.is_unique, i.is_disabled, i.has_filter
   ,ic.index_column_id, c.[name] AS column_name
   ,CASE WHEN ic.is_descending_key = 0 THEN 'ASC'
        ELSE 'DESC'
    END AS [order]
    ,ic.is_included_column
FROM
   sys.schemas s
   INNER JOIN
   sys.tables t
      ON   t.schema_id = s.schema_id
   INNER JOIN
   sys.indexes i
      ON   i.object_id = t.object_id
   INNER JOIN
   sys.index_columns ic
      ON   ic.object_id = t.object_id
      AND   ic.index_id = i.index_id
   INNER JOIN
   sys.columns c
      ON   c.object_id = t.object_id
      AND   ic.column_id = c.column_id
WHERE   i.index_id > 0
   AND   i.type IN ( 1 ,2 ) -- clustered & nonclustered only
   AND   i.is_hypothetical = 0
   AND t.[object_id] = OBJECT_ID('$OBJECT$')
   AND i.index_id = $idix$
ORDER BY
   i.[name]
   ,ic.index_column_id
$$

Wed Aug 24, 2011 5:30 am View user's profile Send private message
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